Nama : Rocky ade nurmansah
kelas : 12.2D.06
NIM : 12131435
TUGAS
Buatlah
ilustrasi tabel, pemetaan RMO & CMO, jalur perpindahan serta hasilnya dalam
hexa array – array dibawah ini :
- 1. Array float A[5] dengan nilai awal A[1] = 002F(H), Berapa nilai A[3] .. ?
- 2. Array float A[10] dengan nilai awal A[8] = 012F(H), Berapa nilai A[3] .. ?
- 3. Array float A[5][4] dengan nilai awal A[1][0] = 002F(H), Berapa nilai A[3][3] .. ?
- 4. Arrary int A[5][4] dengan nilai awal A[3][3] = 00CF(H), Berapa nilai A[0][1] .. ?
JAWAB :
1)
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002F(H)
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?
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A[i] = A[3]
B = 002F(H)
i = 3
L = 4
B = 002F(H)
i = 3
L = 4
A[i] = B + (i – 1) * L
A[3] = 2F(H) + (3 – 1) * 4
A[3] = 2*15(H) + 8(D)
A[3] = 30(H) + 8(H)
A[3] = 38(H)
A[3] = 2F(H) + (3 – 1) * 4
A[3] = 2*15(H) + 8(D)
A[3] = 30(H) + 8(H)
A[3] = 38(H)
2).
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012F(H)
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A[i] = A[3]
B = 12F(H)
i = 3
L = 4
B = 12F(H)
i = 3
L = 4
A[i] = B + (i – 1) * L
A[3] = 12F(H) + (3 – 1) * 4
A[3] = 12*15(H) + 8(D)
A[3] =180(H) + 8(H)
A[3] = 188(H)
A[3] = 12F(H) + (3 – 1) * 4
A[3] = 12*15(H) + 8(D)
A[3] =180(H) + 8(H)
A[3] = 188(H)
3).
Arrray
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002F(H)
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3
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Ditanya ?
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Jalur perpindahan : A[0][0]
- A[0][1] - A[0][2] - A[0][3] - A[1][1] - A[1][2] - A[1][3] - A[2][0] - A[2][1]
- A[2][2] - A[2][3] - A[3][0] - A[3][1] - A[3][3]
Hasil : A[3][3] = 002F(H) + { (5-1) * 3 + (4-1) * 4
A[3][3] = 2”15(H) + 4 * 3 + 3 * 4
A[3][3] = 30 + 12 + 12
= 54(D) = 36(H)
4).
Arrray
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Ditanya ?
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00CF(H)
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Jalur perpindahan : A[0][0]
- A[0][1]
Hasil : A[0][1] = 00CF(H) + { (5-1) * 3 + (4-1) * 2
A[0][1] = 207(H) + 4 * 3 + 3 * 2
A[0][1] = 207 + 12 + 6
= 225(D) = E1(H)
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